The perimeter of an isosceles triangle is 24cm. The length of its congruent sides is 13cm less than twice the length of its base. Find the lengths of all sides of the triangle.
Answers
Answer:
The length of its congruent sides is 13 cm less than twice the length of its base. ... Solution : Let the length of the base of the isosceles triangle be x cm and the length of congruent sides be y cm. Then from the given conditions, Perimeter of triangle = 24 cm.
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Answer:
7 cm, 10 cm, 7 cm
Step-by-step explanation:
Let the length of the base be x and the congruent side of triangle be y respectively.
Perimeter of triangle :- c + a + b = 24
( x + y + y =24)
Therefore, x + 2y = 24 --(1)
According to the given condition we get,
y = 2x - 13
13 = 2x - y --(2) [ Multipy it with 2 ]
26 = 4x - 2y
4x - 2y = 26 --(3)
Adding equation (1) & (3) We get,
x + 2y = 24
4x -2y = 26
• 4x + x = 5 x
• 2y -2y = 0
• 24+26 = 50
5x = 50
x = 50/5
x = 10
Therefore, the base of an given isosceles triangle is 10 cm.
Substituting the value of x = 10 in equation (1)
x + 2y = 24
10 + 2y = 24
2y = 24 - 10
2y = 14
y = 14/ 2
y = 7
Therefore, the congruent side of the given triangle if 7 & 7 cm respectively.