The perimeter of an isosceles triangle is 27cm.The length of its base is 3 cm less than the two equal sides.Find the lengths of the sides.
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Let a,a,a-3 be the lengths of sides of triangle
perimeter = a+a+a-3
= 3a-3
3a-3 = 27
a = 27+3/3
a = 30/3
a = 10
Therefore,
a = 10
a - 3 = 10 - 3
= 7
Hope this clears ur doubt
perimeter = a+a+a-3
= 3a-3
3a-3 = 27
a = 27+3/3
a = 30/3
a = 10
Therefore,
a = 10
a - 3 = 10 - 3
= 7
Hope this clears ur doubt
ankurgamit2313ot8bcd:
wrong
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