the perimeter of an isosceles triangle is 32 centimetre the ratio of the equal side to its base is 3 by 2 find area of the triangle
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Let the sides be 3x,3x,2x
3x + 3x+ 2x = 32
8x = 32
x = 4
Therefore sides are 12,12,8
semi perimeter = 16
Area = √(16-12)(16-12)(16-8)
= √(4)(4)(8)
= 32√2 cm²
3x + 3x+ 2x = 32
8x = 32
x = 4
Therefore sides are 12,12,8
semi perimeter = 16
Area = √(16-12)(16-12)(16-8)
= √(4)(4)(8)
= 32√2 cm²
iswar7:
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