Question

The perimeter of an isosceles triangle is 32 cm. The ratio of the equal
side to its base is 3: 2. Find the area of the triangle

Answer 1

Answer:

According to the question

Perimeter of the isosceles triangle = 32

it is also given that,

Ratio of equal side to base = 3 : 2

Let the equal side = 3x

So, base = 2x

Perimeter of the triangle = 32

⇒ 3x + 3x + 2x = 32

⇒ 8x = 32

⇒ x = 4

Equal side = 3x = 3×4 = 12

Base = 2x = 2×4 = 8

The sides of the triangle = 12cm, 12cm and 8cm.

Let a = 12, b = 12, c = 8

s = (a + b + c)/2

⇒ s = (12 + 12 + 8)/2 = 32/2 = 16

Area of the triangle = √s(s-a)(s-b)(s-c)

= √16(16-12)(16-12)(16-8)

= √16×4×4×8

= 32√2 cm2

Step-by-step explanation:

hope this will help you

Answer 2

[ Refer to the Attachment ]

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