Math, asked by Anonymous, 1 year ago

The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to the base is 3:2 . Find area of the triangle.

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Answered by Anonymous

Let the sides are 3x, 3x, 2x.
3x+3x+2x=32
8x=32
x=4
3x=12 cm
2x=8 cm
S=32/2=>16
Area=√16(16-12)(16-12)(16-8)
= √16×4×4×8
=32√2 cm²

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Answered by anupamaraj

3:3:2=32cm Equal sides are 12cm and base is 8cm h=√144-16=√128=8√2cm Area=1/2 x b x h =1/2 x 8 x 8√2 sq cm =4 x 8√2 sq cm =32√2 sq cm

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