Math, asked by anikesh72, 1 year ago

the perimeter of an isosceles triangle is 32cm the ratio of the equal sides to its base is 3:2 find the area of the triangle

Answers

Answered by harshranaji
20

hey mate here is your answer

the perimeter of isosceles triangle = 32cm

p of isosceles triangle = 2 * equal side + base

let length of equal side be 3x and base be 2x

then

2 * 3x + 2x = 32 cm

6x + 2x = 32cm

8x = 32 cm

x= 4 cm

length of equal side = 3*4= 12cm

length of base = 2*4=8cm

area of isosceles triangle=b*1/4*√4a2-b2

= 8*1/4√4*144-64

=2√512

=2*22.62

= 45.25cm2


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