Question

The perimeter of an isosceles triangle is 34 cm. One of its sides is 7 cm more than the other side. Find all three sides of the triangle.

Answer 1

Let each of the equal side = x
Now , the third side = x+7

Perimeter = 34 cm
Sum of all sides = 34
x+x+x+7 = 34
3x=34-7
3x=27
x=27/3
x=9

Each of the equal side = x=9 cm
x=9 cm
x+7 = 9+7 = 16 cm .

The required sides of the triangle = 9,9,16 cm .

Perimeter is the sum of all sides .

$\huge{Be\:Brainly}$

Answer 2

HEY MATE !!!!!!!!!

HERE IS YOUR ANSWER !!!

As in isosceles triangle , 2 sides are equal so let in triangle ABC , AB=AC =x

the third side is 7 cm more , so BC = x+7

PERIMETER = sum of all sides

34cm = AB + BC+AC

34 = x +x+x+7

27=3x

x = 9cm

AB=AC=X=9cm

while , BC = x+7 = 16cm

hope it helps !!!

thnx :}