The perimeter of an isosceles triangle is 40 CM. The base is two third of the sum of equal sides. Find the length of each side.
Answers
Answered by
194
let the equal sides be x
base = 2/3 ( x + x ) = 2/3 (2x) = 4x/3
ATQ
x + x + 4x/3 = 40
3x + 3x + 4x = 120
10x = 120
x = 12
the sides are -
12 cm
12 cm
16 cm
base = 2/3 ( x + x ) = 2/3 (2x) = 4x/3
ATQ
x + x + 4x/3 = 40
3x + 3x + 4x = 120
10x = 120
x = 12
the sides are -
12 cm
12 cm
16 cm
maria9:
welcm :)
please mark as brainliest ^_^
If the equal side is 12 cm, then according to this base will be 8 cm because it is two third of equal sides.
2/3 of sum of equal sides
please read the Q carefully
sorry, i got the point, your answer is correct...thanks
np :)
what is np?
np = no problem
okay...☺☺☺
Answered by
43
Let the sides be of length x cm
Sum of two equal sides is x+x = 2x cm
Therefore base = 2x/3 cm
A/Q,
2x + 2x/3 = 40
(6x+2x) / 3 = 40
8x/3 = 40
8x = 40*3
x = 120/8
x = 15
so, the length of equal sides = 15 cm
& length of base = 2x/3 = 30/3 = 10 cm
Hope it will help you !!!
Sum of two equal sides is x+x = 2x cm
Therefore base = 2x/3 cm
A/Q,
2x + 2x/3 = 40
(6x+2x) / 3 = 40
8x/3 = 40
8x = 40*3
x = 120/8
x = 15
so, the length of equal sides = 15 cm
& length of base = 2x/3 = 30/3 = 10 cm
Hope it will help you !!!
ur answer is wrong
Similar questions