Question

the perimeter of an isosceles triangle is 42 cm and its base is 3/2 times of the equal sides
1) find lenght of each side
2) area
3) altitude on longest side​

Answer 1

Step-by-step explanation:

perimeter =42m

equal sides=x

base=3x/2

42=x+x+3x/2

42=2x+3x/2

lcm of 1 and 2 is 2

42=(2x×2/1×2)+3x/2

42×2=7x/2×2

84/7=7×/7

12=x

1)equal sides =12m

base=3x/2

3×12/2

36/2

18m

2)a=(b/2)²×(h)² (pythogaurus theorem)

12²=(18/2)²×h²

144=9²×h²

144=81×h²

144-81=h²

63=h²

h=7.93

h=8m

area=1/2(h×b)

area=1/2(8×18)

area=1/2×144

area=72m²

3)8m