Question

The perimeter of an isosceles triangle is is 40 cm .The base is two third of the sum of equal sides. Find the length of each side ​.

Answer 1

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Answer:

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Let the equal sides be x

base = 2/3 ( x + x ) = 2/3 (2x) = 4x/3

ATQ

x + x + 4x/3 = 40

3x + 3x + 4x = 120

10x = 120

x = 12

the sides are -

12 cm

12 cm

16 cm

Hope it helps you ✌️✌️❤️❤️

Answer 2

Answer:- AB=12,BC=12,CA=16

Step-by-step explanation:

Let the equal sides be x

base = 2/3 ( x + x ) = 2/3 (2x) = 4x/3

ATQ

x + x + 4x/3 = 40

3x + 3x + 4x = 120

10x = 120

x = 12

the sides are -

12

12

16