The perimeter of an isosceles triangle is is 40 cm .The base is two third of the sum of equal sides. Find the length of each side .
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Answered by
2
Hey buddy ❤️❤️
Answer:
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Let the equal sides be x
base = 2/3 ( x + x ) = 2/3 (2x) = 4x/3
ATQ
x + x + 4x/3 = 40
3x + 3x + 4x = 120
10x = 120
x = 12
the sides are -
12 cm
12 cm
16 cm
Hope it helps you ✌️✌️❤️❤️
Answered by
0
Answer:- AB=12,BC=12,CA=16
Step-by-step explanation:
Let the equal sides be x
base = 2/3 ( x + x ) = 2/3 (2x) = 4x/3
ATQ
x + x + 4x/3 = 40
3x + 3x + 4x = 120
10x = 120
x = 12
the sides are -
12
12
16
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