Question

the perimeter of an isoseles triangle is 40 cm the base is two third of the sum of equal sides find the length of each side
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Answer 1

Answer:

Step-by-step explanation:

Let the sides be of length x cm

Sum of two equal sides is x+x = 2x cm

Therefore base = 2x/3 cm

A/Q,

2x + 2x/3 = 40

(6x+2x) / 3 = 40

8x/3 = 40

8x = 40*3

x = 120/8

x = 15

so, the length of equal sides = 15 cm

& length of base = 2x/3 = 30/3 = 10 cm

Answer 2

Perimeter of an isosceles triangle = 40cm

Let the length of the equal sides be x

Length of the base is

$\frac{2x}{3}$

So,

$x + x + \frac{2x}{3} = 40$

$2x + \frac{2x}{3} = 40$

$\frac{6x + 2x}{3} = 40$

$8x = 120$

$x = 15$

Therefore the length of the equal sides is equal to 15cm and the length of the base is 10cm