Math, asked by arasheedpk77, 11 months ago

the perimeter of asector of a circle of radius 8 cm s 25 m what is the area of the sector ​

Answers

Answered by Anonymous
3

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Solution

Let POQ be the given sector!!

Given:-

Radius (r) of circle =) 8 cm

Given:- Perimeter of sector POQ = 25 cm

Note: Perimeter = All sides adding

Now,

So, OP + OQ + Arc PQ = 25 cm

8 + 8 + Arc PQ = 25 cm

Arc PQ = 25 -16 cm

Arc PQ = 9 cm

According to the Question!!

 l = Arc length PQ = 9 cm

Therefore,

Area of sector POQ = 1/2 × r × l

=  8 x 9 / 2

= 72/ 2

= 36 cm²

Hence, Area of Sector = 36 cm²

Answered by DeviIQueen
0

Answer:

Solution⭐

Let POQ be the given sector!!

Given:-

Radius (r) of circle =) 8 cm

Given:- Perimeter of sector POQ = 25 cm

Note: Perimeter = All sides adding

Now,

So, OP + OQ + Arc PQ = 25 cm

8 + 8 + Arc PQ = 25 cm

Arc PQ = 25 -16 cm

Arc PQ = 9 cm

According to the Question!!

l = Arc length PQ = 9 cm

Therefore,

Area of sector POQ = 1/2 × r × l

= 8 x 9 / 2

= 72/ 2

= 36 cm²

Hence, Area of Sector = 36 cm²

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