the perimeter of atringle is 5 -3x +)7x^2 and two sides are 2x^2+3x-2and 3x^2 -x + 3 . find third
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(2x^2+3x-2)+3x^2-x+3=5x^2+2x+1
5-3x+7x^2-(5x^2+2x+1)
=4-5x+2x^2 is the third side
5-3x+7x^2-(5x^2+2x+1)
=4-5x+2x^2 is the third side
nishant45:
is it correct
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The third side :
2x^2 - 5x + 4
2x^2 - 5x + 4
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