Question

The perimeter of isoceles triangle is 24cm ,length of it's congruent sides is 13 cm less than twice the length of base ,find the length of all sides of triangle

Answer 1

Answer:

Let the length of the base of the isosceles triangle be x cm and the length of congruent sides be y cm.

Then from the given conditions,

Perimeter of triangle = 24 cm.

∴ x + y + y = 24

∴ x + 2y = 24 ............. eq. no. (1)

According to second condition,

y = 2x – 13

∴ 2x – y = 13 ................. eq. no. (2)

Multiplying equation (2) by 2 we get

4x – 2y = 26 ................. eq. no. (3)

Adding equation (1) and (3)

x + 2y = 24

4x – 2y = 26

5x     =   50

∴ x = 50/5

∴ x = 10

Substituting x = 10 in eq. (1)

x + 2y = 24

∴ 10 + 2y = 24

∴ 2y = 24 – 10

∴ 2y = 14

∴ y = 14/2

∴ y = 7.

hope this helps bro

Answer 2

Answer: 10 cm, 7 cm, 7 cm

Step-by-step explanation: Let the length of the base be x cm.

Therefore, length of congruent sides is (2x-13) cm.

Perimeter = 24 cm

Perimeter = x + 2(2x-13)                                       [ (2x-13) + (2x-13) = 2(2x-13) ]

24 = x + 4x-26

50 = 5x

x = 10 cm

(2x-13) = 7 cm