Question

The perimeter of isosceles triangle is 32cm the ratio of the equal side to its base is 3:2 find the area of triangle

Answer 1

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Answer 2

$\huge\mathfrak{Answer}$

Let the equal side is 3x cm and base is 2x cm respectively.

3x + 3x + 2x = 32

8x = 32

=> x = 4cm

$area \: \sqrt{s(s - a(s - b(s - c)}$

$\sqrt{16(16 - 12)(16 - 12)(16 - 8)}$

$\sqrt{16 \times 4 \times 4 \times 8}$

$\sqrt{4 \times 4 \times 4 \times 4 \times 4 \times 2}$

$= 32 \sqrt{2 \: {cm}^{2} }$