The perimeter of one square is 748 cm and that of another square is 336 cm. Find the perimeter of a square which is equal in area of the sum of the two
Answers
☞ Answer :
Perimeter of the required square = 820 cm.
☞ Given :
- Perimeter of square (1) = 748 cm.
- Perimeter of square (2) = 336 cm.
☞ To Find :
Perimeter of the required square (3).
☛ How To Find :
We know,
Side of square = Perimeter/4
∴ Side of square (1) = 748/4 = 187 cm.
∴ Area of square (1) = (side)² = (187)² =
34969 cm²
Side of square (2) = 336/4 = 84 cm.
∴ Area of another square = (84)² = 7056 cm²
Now, sum of areas of squares = 34969 + 7056
= 42025 cm²
Again, area of square(3) = sum of areas of squares (1) & (2)
= 42025 cm²
∴ Side of third square = = 205 cm
∴Perimeter of square (3) = 4 × side of square (3)
= 4 × 205 = 820 cm
∴ Perimeter of the required square = 820 cm.
Step-by-step explanation:
lets take two squares,
A and B,
let A =748cm
and B=336cm
according to the formula,
side of a square = perimeter/4
thus ,
1. side of square A =748cm/4=187cm
2.side of the square B=336cm/4=84cm
as we know ,
Area of a square = side ×side
then,
1.area of square A=187cm×187cm=34969sq.cm
2.Area of square B=84cm×84cm=7056sq.cm
Sum of the area of the square =Area of square A +Area of square B
- sum of the area of the square=34969sq.cm+7056sq.cm
sum of areas of the square =42025sq.cm
thus ,
let the new square formed by adding the area be C
Area of square C=42025sq.cm
Side of a square= root of its Area
Side of square C=root of 42025 Sq.cm
205cm
as 205cm ×205 cm =42025sq.cm
thus ,
side of square C=205 cm
now,
Perimeter of a square = 4×side
Perimeter of Square C=4×205 cm
=820cm