the perimeter of rectangle is 110/7 and its length is 3/7 find the breadth
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Answer:
perimeter of rectangle = 2(l+b)
110/7 = 2(3/7+b)
110/7=2(3+7b)/7
110=6+14b
b = 7.428
Answered by
0
Answer:
Perimeter of rectangle =2(l+b)
110/7=2(3/7+b)
110/7=2(3+7b)/7
110=6+14b
B=7.428
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