Question

The perimeter of rectangle is 13 cm and it's width is 2 3/4 cm find it's length

Answer 1

Answer:

3.7 cm

Step-by-step explanation:

perimeter = 2(l + b)

13 = 2(11/4 + l)

13 = 22/4 + 2l

2l = 13-22/4

2l = 30/4

l = 30/8

= 3.7 cm

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\bullet Width\:of\: rectangle=2\dfrac{3}{4}= \dfrac{11}{4}cm\\ \\ \sf\bullet Perimeter=13cm$

Now

$\boxed{\sf{Perimeter \:of\: rectangle=2(length+breadth)}}$

$\bf\underline{\red{\:\:\:\:\:\:\:\:A.T.Q:-\:\:\:\:\:\:\:}}$

$\sf\implies 2(length+\dfrac{11}{4})=13\\ \\ \sf\implies length+\dfrac{11}{4}=\dfrac{13}{2}\\ \\ \sf\implies length=\dfrac{13}{2}-\dfrac{11}{4}\\ \\ \sf\implies length=\dfrac{26-11}{4}\\ \\ \sf\implies length=\dfrac{15}{4} \\ \\ \sf\implies length=3\dfrac{3}{4}$

$\boxed{\sf{length=3\dfrac{3}{4}cm}}$