The perimeter of rectangle is 28 m, whereas its area is 48m2. what is the lenght of its
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firstly apply perimeter formula of rectangle
2(l+b)=28
l+b=14......(i)
then area =l×b
l×b=48
l=48/b
replace the value of b in first equation
then 48/b+b=14
48+b^2=14b
b^2-14b+48=0
b^2-8b-6b+48=0
and then you solve iy
2(l+b)=28
l+b=14......(i)
then area =l×b
l×b=48
l=48/b
replace the value of b in first equation
then 48/b+b=14
48+b^2=14b
b^2-14b+48=0
b^2-8b-6b+48=0
and then you solve iy
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