Question

the perimeter of rectangle is 80m.if in legth is decrease by 2 and wide increases by 2 then area of rectangle is 36sq m.find the legth and wide of rectangle

Answer 1

$x + y = 40 \\ (x - 2)(y + 2) = 36$
after solving these two equations we will get
$y = - 1 \\ y = 50 \\ x = - 10 \\ x = 41$