The perimeter of rectangle is 98 cm and length of diagonal is 41 cm find area of the rectangle
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perimeter of rectangle =98
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Let the width be = b
and
Let the length be = L
Area of rectangle = L × b
Perimeter of rectangle = 2 ( L + b )
2 ( L + b ) = 98
L + b = 49
Squaring both sides
( L + b )² = ( 49 )²
L² + b² = 2401 - 2 ( L × b )
By p.g.t
( 41 )² = L² + b²
=>
( 41 )² = 2401 - 2 ( L × b )
L × b = 360cm²
So, area of rectangle = 360cm²
Have a nice day ahead..
Let the width be = b
and
Let the length be = L
Area of rectangle = L × b
Perimeter of rectangle = 2 ( L + b )
2 ( L + b ) = 98
L + b = 49
Squaring both sides
( L + b )² = ( 49 )²
L² + b² = 2401 - 2 ( L × b )
By p.g.t
( 41 )² = L² + b²
=>
( 41 )² = 2401 - 2 ( L × b )
L × b = 360cm²
So, area of rectangle = 360cm²
Have a nice day ahead..
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