the perimeter of rectangle is52 cm the lenght is 2 more than twice its width find the dimensions of rectangle
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Let B=x
L=2+2x
x+x+2+2x+2+2x=52
6x+4=52
6x=52-4
6x=48
x=48/6
x=8
Breadth=8cm
Length=2+2×8=2+16=18cm.
L=2+2x
x+x+2+2x+2+2x=52
6x+4=52
6x=52-4
6x=48
x=48/6
x=8
Breadth=8cm
Length=2+2×8=2+16=18cm.
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