the perimeter of rectangles is 40m the length of the rectangles is 4cm less than 5 times it's breadth find the length of rectangles
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Answered by
18
Let Breadth of rectangle be X cm.
Length of rectangle = ( 5X - 4 ) cm.
Perimeter of rectangle = 4000 cm
2 ( Length + Breadth ) = 4000 cm.
2 ( 5X - 4 + X ) = 4000
2 ( 6X - 4 ) = 4000
6X - 4 = 2000
6X = 200 + 4
6X = 2004
X = 204/6
X = 334 cm
Breadth of rectangle = X = 334 cm.
And,
Length of rectangle = 5X - 4 = 1666 cm.
Length of rectangle = ( 5X - 4 ) cm.
Perimeter of rectangle = 4000 cm
2 ( Length + Breadth ) = 4000 cm.
2 ( 5X - 4 + X ) = 4000
2 ( 6X - 4 ) = 4000
6X - 4 = 2000
6X = 200 + 4
6X = 2004
X = 204/6
X = 334 cm
Breadth of rectangle = X = 334 cm.
And,
Length of rectangle = 5X - 4 = 1666 cm.
Answered by
3
Let the length of it's breadth be x cm and then length will be ( 5x - 4 ) cm [ 4 cm less than 5 times of x ]
Given,Perimeter of rectangle = 40 m = 4000 cm
We Know, Perimeter of rectangle is 2( length + breadth )
So, 2[ x + ( 5x - 4 ) ] = 4000
=> x + 5x - 4 = 2000
=> 6x = 2000 + 4
=> 6x = 2004
=> x = 2004 / 6
=> x = 334
Hence,Breadth = x = 334 cm and length = 5( 334 ) - 4 = 1666 cm
Given,Perimeter of rectangle = 40 m = 4000 cm
We Know, Perimeter of rectangle is 2( length + breadth )
So, 2[ x + ( 5x - 4 ) ] = 4000
=> x + 5x - 4 = 2000
=> 6x = 2000 + 4
=> 6x = 2004
=> x = 2004 / 6
=> x = 334
Hence,Breadth = x = 334 cm and length = 5( 334 ) - 4 = 1666 cm
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