Question

The perimeter of rectangular gardenia 160m.If it is 10m wide,find it's area.

Answer 1

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Answer 2

$\boxed{\boxed{\boxed{\bold{\green{Solution : \longrightarrow}}}}}$

$\bold{For \: \: the \: \: rectangular \: \: gardenia}$

$\bold{Perimeter = 160 \: m} \\ \\ \bold{Wide \: (b) = 10 \: m}$

$\bold{\underline{To \: \: find \: \: length \: (l)}}$

$\bold{We \: \: know \: \: that}$

$\bold\red{Perimeter \: \: of \: \: rectangle = 2(l + b)} \\ \\ \bold{= > 160 \: m = 2(l + 10 \: m)} \\ \\ \bold{= > 160 \: m = 2l + 20 \: m} \\ \\ \bold{= > 160 \: m - 20 \: m = 2l} \\ \\ \bold{= > 2l = 140 \: m} \\ \\ \bold{= > l = \frac{140 \: m}{2}} \\ \\ \bold{= > l = 70 \: m}$

$\bold{Now,}$
$\bold{\underline{To \: \: find \: \: area}}$

$\bold{We \: \: know \: \: that}$

$\bold\blue{Area \: \: of \: \: rectangle}\\ \\ \bold{ = Length \times Breadth}\\ \\ \bold{ = (70 \times 10) \: {m}^{2}} \\ \\ \bold{ = 700 \: {m}^{2} }\: \: \: \boxed{\boxed{\boxed{\bold{\purple{Ans}}}}}$

$\boxed{\bold{\purple{Have \: \: a \: \: nice \: \: day.}}}$