the perimeter of rectangular piece of paper is 56 CM if the length is 3 times of its what is its width
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Answered by
10
Let the width be z
Then length = 2Z
ATQ
Perimeter of rectangle = 2(l+b)
→56= 2(3z+z)
→56= 2*4z
→z= 56/8
→z= 7cm
Breadth= 7cm
Length= 3z= 3*7= 21cm
Thank You....
Hope this will be helpful for you.
Then length = 2Z
ATQ
Perimeter of rectangle = 2(l+b)
→56= 2(3z+z)
→56= 2*4z
→z= 56/8
→z= 7cm
Breadth= 7cm
Length= 3z= 3*7= 21cm
Thank You....
Hope this will be helpful for you.
Answered by
1
Step-by-step explanation:
Let the width be x
Then length = 2Z
Perimeter of rectangle = 2(l+b)
→56= 2(3x+x)
→56= 2*4x
→x= 56/8
→x= 7 cm
Breadth= 7 cm
Length= 3x= 3*7= 21 cm
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