the perimeter of sq is 44 cm the perimeter of rectangle is equal to the perimeter of this square the length of the rectangle is 5 cm more then the side of square the sum of areas (in cm square) of the square and the rectangle is?
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Answer:
p of square =4s
44=4s
s=11cm
area of square = s^2
= 11^2
=121cm^2
the side of rectangle are
length = s +5
11+5
= 16 cm
p of rectangle = 2(l+b)
44cm= 2 (16+b)
44/2 =16+b
22-16 =b
b= 6 cm
area of rectangle= l*b
= 16*6
= 96 cm^2
total area = 96 + 121
= 217 cm^2
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