the perimeter of square and rectangle are equal if the sides of the square is 8 cm and the length of rectangle is 12 cm find the breadth of the rectangle
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4a = 2(l+b)
4*8 = 2(12+b)
32 = 24+2b
2b = 8
b = 4
4*8 = 2(12+b)
32 = 24+2b
2b = 8
b = 4
Answered by
2
perimeter of square=4×8
=32
perimeter of rectangle = 2(12+b)
32. =2(12+b)
b=4
=32
perimeter of rectangle = 2(12+b)
32. =2(12+b)
b=4
savita077:
hloo
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