the perimeter of square is 56 m the area of the rectangle is 8 sq.m. less than the area given square .if the length of the rectangle is 16 m , find the breadth
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P.of square=4*side
∴56=4×side
∴side=56÷4=14
∴A.of square=(side)²
=(14)²=196
A.of rectangle= A.of square-8
=196-8=188
A.of rectangle=l×b
188 =16×b
∴ b=188÷16=11.75
≈12
∴Breadth of rectangle is 12m.
∴56=4×side
∴side=56÷4=14
∴A.of square=(side)²
=(14)²=196
A.of rectangle= A.of square-8
=196-8=188
A.of rectangle=l×b
188 =16×b
∴ b=188÷16=11.75
≈12
∴Breadth of rectangle is 12m.
shammu2:
thanks so much
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