the perimeter of the base of a cone is 44 cm and the slant height is 25 cm find the volume and the curved surface of the cone
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Perimeter of the base of a cone = 44.
2πr = 44
2 × 22/7 × r = 44
r = ( 44 × 7 ) / 44
r = 7 cm.
Radius of cone ( r ) = 7 cm.
Slant height ( L ) = 25 cm.
Height ( H ) = ?
We know that,
Slant height of cone = ✓( Radius)² + (Height)²
(Slant height)² = Radius² + Height²
Height² = √(Slant height)² - (Radius)²
Height² = ✓(25)² - (7)²
Height² = 576
Height = √576 = 24 cm.
Height of cone ( H ) = 24 cm.
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Volume of cone = 1/3 πr² H
=> 1/3 × 22/7 × 7 × 7 × 24
=> (22 × 7 × 8 ) cm³.
=> 1232 cm³.
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Curved surface area of cone = πrL
=> 22/7 × 7 × 25
=> ( 22 × 25 ) cm².
=> 550 cm².
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2πr = 44
2 × 22/7 × r = 44
r = ( 44 × 7 ) / 44
r = 7 cm.
Radius of cone ( r ) = 7 cm.
Slant height ( L ) = 25 cm.
Height ( H ) = ?
We know that,
Slant height of cone = ✓( Radius)² + (Height)²
(Slant height)² = Radius² + Height²
Height² = √(Slant height)² - (Radius)²
Height² = ✓(25)² - (7)²
Height² = 576
Height = √576 = 24 cm.
Height of cone ( H ) = 24 cm.
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Volume of cone = 1/3 πr² H
=> 1/3 × 22/7 × 7 × 7 × 24
=> (22 × 7 × 8 ) cm³.
=> 1232 cm³.
-----------------------------------------------
Curved surface area of cone = πrL
=> 22/7 × 7 × 25
=> ( 22 × 25 ) cm².
=> 550 cm².
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