the perimeter of the base of a room is 25m it's height is 6m then the area of 4walls
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Perimeter of Base = 25 m
2(L+B) = 25 -------(1)
Height = 6 m
Area of four walls = 2(L+B) * H
= 25 * 6
= 150 m^2
2(L+B) = 25 -------(1)
Height = 6 m
Area of four walls = 2(L+B) * H
= 25 * 6
= 150 m^2
Answered by
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hiii!!!
here's ur answer...
perimeter of the base of the room is 25m
therefore 2(l+b) is 25m.
given the height of the room is 6m.
we have to find the area of the four walls of room, hence we will use CSA.
CSA = 2h(l+b)
we can also write it as 2(l+b)×h
area of the four walls = 25×6
= 150m²
hope this helps u...!
here's ur answer...
perimeter of the base of the room is 25m
therefore 2(l+b) is 25m.
given the height of the room is 6m.
we have to find the area of the four walls of room, hence we will use CSA.
CSA = 2h(l+b)
we can also write it as 2(l+b)×h
area of the four walls = 25×6
= 150m²
hope this helps u...!
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