the perimeter of the certain sector of a circle of radius 5.6 is 27.2 M find the area of the sector
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area of sector =x/360 ×πr×r so90/360×22/7× 5.6×5.6=2.464
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Answer:
The Area of sector is 44.8 m².
Step-by-step explanation:
Given:
Radius of a circle(OA,OB) ,r = 5.6 m
Perimeter of the sector of a circle = 27.2 m
Let OAB be the given sector.
Perimeter of the sector , OAB = 27.2 m
OA + OB + Arc AB = 27.2 m
5.6 + 5.6 + Arc AB = 27.2
11.2 + Arc AB = 27.2 m
Arc AB = 27.2 - 11.2 = 16.0 m
Length of the sector , AB(l) = 16.0 m
Area of sector OAB = ½ × l × r
= ½ × (16)(5.6)
= 8 × 5.6
Area of sector OAB = 44.8 m²
Hence, the Area of sector = 44.8 m².
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