Question

the perimeter of the floor of a wooden packing box is thrice of the height of the box is the area of the four walls of the box is 2883 square centimetre find the perimeter of the floor of the box​

Answer 1

The perimeter of the floor of the wooden packing box is thrice of the height of the box.

∴ Let 'p' be the perimeter of 'h' will be the height of the box, then -

∴ P = 3h → 1 = h = $\frac{P}{3}$ → 2

Area of four walls of the rooms = 2883cm²

∴ 2h ( l + b ) = 2883

→ 2 × $\frac{P}{3}$ ( l + b ) = 2883

→ 2 × P ( l + b ) = 2883 × 3

→ P (2 ( l + b ) ) = 8649 → 3

Perimeter of the floor of the box = 2 ( l + b ) umb,

∴ P  =  (2 ( l + b ) )  → 4

From 4     3 becomes

∴ P  ( P ) = 8649

              = p² = 8649

              = p = $\sqrt{8649}$

              ∴ p = 53 cm

∴ perimeter of floor = 93cm

∴ Perimeter of the floor on the wooden box = 93cm

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Answer 2

Answer:

93 cm

Step-by-step explanation:

The perimeter of the floor of the wooden packing box is thrice of the height of the box.

∴ Let 'p' be the perimeter of 'h' will be the height of the box, then -

∴ P = 3h → 1 = h = \frac{P}{3}

3

P

→ 2

Area of four walls of the rooms = 2883cm²

∴ 2h ( l + b ) = 2883

→ 2 × \frac{P}{3}

3

P

( l + b ) = 2883

→ 2 × P ( l + b ) = 2883 × 3

→ P (2 ( l + b ) ) = 8649 → 3

Perimeter of the floor of the box = 2 ( l + b ) umb,

∴ P = (2 ( l + b ) ) → 4

From 4 3 becomes

∴ P ( P ) = 8649

= p² = 8649

= p = \sqrt{8649}

8649

∴ p = 53 cm

∴ perimeter of floor = 93cm

∴ Perimeter of the floor on the wooden box = 93cm(Ans)