Question

The perimeter of the rectangle room is 160 m .if the lenght and the breadth are in the ratio 3:5 ,find the area of the room

Answer 1

let breadth be 3x

length=5x

perimeter = 2(l+b)

160= 2(5x+3x)

160=16x

x= 10

length=50

breadth= 30

area = lb

50*30

1500 m^2

Answer 2

Hi,
Here is the solution
➖➖➖➖➖➖➖➖

$ratio \: of \: length \: and \: bredth = 3x \: and \: 5x \\ \\ so \\ perimeter \: of \: rectangle == > 2(length + bredth) \\ \\ = = > 2(3x + 5x) = 160 \\ \\ = = > 2(8x) = 160 \\ \\ = = > x = \frac{160}{16} \\ \\ = = > x = 10 \\ \\ so \: the \: length \: (5x) = 50 \\ and \: bredth(3x) = 30 \\ \\ now \\ area \: of \: rectangle \: = (length \times bredth) \\ \\30 \times 50 \\ \\ = = > 1500 {m}^{2}$