Question

the sum of the digit of a two digit number is 12 if the digits are reversed the new number increase e by 36 find the number

Answer 1

let the digit at ones place be x
and digit at tens placeee be y
accor to ques
x+y=12 eq 1
second situation
x+10y=10x+y+36 eq2
frm 1. x=12-y eq. 3
put in eq 2
12-y+10y=10(12-y)-y+36
12+9y=120-10y-y+36
12+9y=120-11y+36
12+9y=-11y+156
12-156=-11y-9y
-144=-20y
y=144%20
y=7.2
x+7.2=12
x=4.8and y=7.2

Answer 2

Hey

Here is your answer,

Let's call the original two digit number xy, where x is the tens digit and y is the ones digit. An algebraic representation of this number is 10x + y.
The sum of the two digit number is 8: x+y=8
When the digits are reversed, the number increases by 36: (10y + x) - (10x + y) = 36

Now we have two equations and two unknown parameters, so we have enough information to find those parameters.

Solve for x:
X=8-y

plug in x:
(10y + 8-y) - (10(8-y)+ y) = 36

simplify:
(9y + 8) - (80-9y) = 36
18y - 72 = 36
y = 108/18 = 6

so if y=6, then x=8-y=8-6=2

so our number is 26. 62 is 36 greater than 26.

Hope it helps you!