Question

The perimeter of the rectangle whose length is 12 cm and a diagonal is 20 cm

Answer 1

We know, (length) ^2 +(breadth)^2=(diagonal)^2

So,

$12^2 + b^2 =20^2 \\ 144+b^2 =400 \\ b^2 =400-144 \\ b^2 =256 \\ b=\sqrt{256} \\ b=16 \\ breadth=16cm$

Answer 2

Answer:

56

Step-by-step explanation:

Here breadth will be 16.

so, perimeter =2(length +breadth)

2(12+16)

2×28

56