Question

the perimeter of the rectangle whose length is 64 cm and a diagonal 80 cm is​

Answer 1

Given

We have given length of Rectangle which is 64cm

One of Diagonal is given which is 80cm

To Find

we have to find the perimeter of Rectangle

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

We know the formula to find out the perimeter of Rectangle

Perimeter of Rectangle=2(length+ breadth)

Formula for finding Diagonal

D²=l²+b²

b²= D²-l²---(1)

Solving for p(perimeter)

=>perimeter = 2l+2(√d²-l²) [from Equation 1]

=>Perimeter of Rectangle= 2×64+2×√(80)²-(64)²

=>perimeter of Rectangle= 128+2×√6400-4096

=>Perimeter of Rectangle= 128+2×√2304

=>Perimeter of Rectangle=128+2×48

=>Perimeter of Rectangle=128+96=224cm

Extra information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Properties of Rectangle:

• A rectangle is a type of quadrilateral.
• Opposite sides are parallel & equal
• Sum of all Interior angles makes 360°
• Diagonals bisects each other and both diagonals are of same length.