The perimeter of triangle ABC is 38 cm.If AB =AC and length of AB greater thanBC by7 cm find the length of sides of triangle ABC
Answers
Answered by
11
Perimeter=38cm
AB=AC=x cm
AB=7+BC
BC=AB-7
BC=x-7
Perimeter=AB+BC+AC
= 38 = x+x-7+x
= 38 = 3x-7
=> 3x = 38+7
= 3x = 45
= x = 45/3
= x = 15cm
AB = 15xm
AC = 15cm
BC =15-7
= 8cm
AB=AC=x cm
AB=7+BC
BC=AB-7
BC=x-7
Perimeter=AB+BC+AC
= 38 = x+x-7+x
= 38 = 3x-7
=> 3x = 38+7
= 3x = 45
= x = 45/3
= x = 15cm
AB = 15xm
AC = 15cm
BC =15-7
= 8cm
Similar questions