Question

the perimeter of triangle is 12 x -7 units the two sides are of length-6 X + 19 and 2 X + 31 units respectively find the length of the third side​

Answer 1

Given Information: The Perimeter of Triangle is 12x-7 units and two of it's sides measures 6x+19 and 2x+31 units respectively.

Need to Find: The Length of the Third side.

Concept:

Here, We are given the perimeter of triangle and the length of two sides of triangle. We have to Find the length of Third side of triangle. We know, the Sum of all sides of triangle equals to the perimeter of triangle i.e, Perimeter of triangle= Length of first side+Length of second side+Lenght of Third side. Equating all the values in the formula will give us the Length of it's Third side.

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Solution:

$\: \: \: \mapsto\tt{Perimeter\: of\: triangle=12x-7}$ $\\\: \: \: \mapsto\tt{Length\: of\: first\: side\: of\: triangle=6x+19}$ $\\\: \: \: \mapsto\tt{Length\: of\: second\: side\: of\: triangle=2x+31}$

Now,

$\\ \: \: \: \: \: \: \: \longrightarrow\sf{Perimeter\: of\: triangle=Length\: of\: first\: side+Lenght\: of\: second\: side+Length\: of\: Third\: side}$

$\\ \: \: \: \: \: \: \: \longrightarrow\sf{12x-7=(6x+19)+(2x+31)+Length\: of\: Third\: side}$

$\\ \: \: \: \: \: \: \: \longrightarrow\sf{12x-7=6x+19+2x+31+Length\: of\: Third\: side}$

$\\ \: \: \: \: \: \: \: \longrightarrow\sf{12x-7=8x+50+Length\: of\: Third\: side}$

$\\ \: \: \: \: \: \: \: \longrightarrow\sf{12x-8x=50+7+Length\: of\: Third\: side}$

$\\ \: \: \: \: \: \: \: \longrightarrow\bold{Length\: of\: Third\: side= \color{red}{4x-57\: units}}$

Required Answer:

Henceforth, Length of third side is 4x-57 units.

Answer 2

your answer dear

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