Question

the perimeter of triangle is 45 CM the longest side exceeds the shortest side by 8cm and the length of the longest and the shorest side is twice the length of other side.find the lengths of side of the triangle

Answer 1

Answer:

Let the length of first side =x

Length of second side =2x

Length of third side =x+5

Perimeter =45cm

x+2x+x+5=454x=45−54x=40x=10

So the sides are

x=10

2x=2×10=20x+5=10+5=15