The perimeter of two similar triangles are 30 cm and 20 cm respectively.If one side of the first triangle is 9 cm long, Find the length of the corresponding side of the second triangle.
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We know that If a/d = b/e = c/f then
each ratio = (a+b+c)/(d+e+f)………….(1)
This concept is used to solve the given problem.
We also know that if two triangles say, ABC and DEF are similar, then the corresponding sides are proportional.
So, if ∆ABC ~ ∆ DEF then
AB/DE = BC/EF= AC/DF
Suppose AB = 15, Also given,
perimeter of ∆ABC/ perimeter of ∆ DEF = 30/20 = 3/2
i.e., (AB+BC+CA)/(DE+EF+DF) = 3/2
Applying (1) AB/DE = 3/2 => 15/DE = 3/2
=> DE = 10 cm
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