Question

the perimeter of two similar triangles are 36 cm and 24 cm the shortest side of the second triangle is 5 cm long find the length of the shortest side of the first triangle​

Answer 1

Answer:

Let △ABC and △DEF be two similar triangles of perimeters P

1

and P

2

respectively.

Also, let AB=12 cm, P

1=30 cm and P 2

=20 cm.

Then,

DE AB= EFBC = DFAC = P 2 P 1

[∵ Ration of corresponding sides of similar triangles is equal to the ratio of their perimeters]

⇒ DEAB = P 2 P 1

⇒ DE 12= 20 30

⇒ DE= 30

12×20 cm=8cm

Hence, the corresponding side of the second triangle is 8 cm