Question

The perimeter of two squares are 40 and 32 respectively .Find the side of the third square whose are is the difference of the area of the previous two squares ​

Answer 1

Answer:

40 = 10

32 = 8

Step-by-step explanation:

difference between 10 and 8 is 2

Answer 2

Answer:

FIRST SQUARE: AREA =S XS

=40 X 40

AREA OF FIRST SQUARE=1600

SECOND SQUARE:AREA = SXS

=32 X 32

AREA OF SECOND SQUARE=1024

THIRD AREA = FIRST AREA - SECOND AREA

                       =  1600-1204

                     AREA=396

396=SXS

2S=396

S=396/2

S=