Math, asked by alpapatel7578, 3 months ago

The perimeter of two squares are 40 cm and 32 cm. The perimeter of at third square whose area is the difference of the are of two square is what ​

Answers

Answered by DarshikaSingh7007
2

Answer:

We know perimeter of square = 4(side)

So Side of first square = 40/4 = 10 cm

Side of second square = 32/4 = 8 cm

Area of third Square = 10*10 - 8*8

= 36 cm

So side of third square = 6 [because area of square = side*side]

Perimeter = 4*Side = 4*6 = 24 cm

Answered by abhiramyalla2105
1

Answer:

area is 36 side is 6

Step-by-step explanation:

giver perimeter of square 1 is 40 cm

so

4×s=40

s=10

so area is 10×10=100.........................1

p

perimeter of square 2 is 32

4×s=32

s=8

so area is 8×8 64...............2

area of third square is

100-64=36

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