Question

The perimeter of two squares are 60 and 144 m.find the perimeter of another square equal in area to the sum of the first two squares

Answer 1

Answer:

• Perimeter of 3rd square = 156 m

Step-by-step explanation:

Given:

• Perimeter of 1st square = 60 m
• Perimeter of 2nd square = 144 m
• Perimeter of another square equal in area to the sum of first two squares.

To Find:

• Perimeter of 3rd square.

Now, Perimeter of 1st square = 60 m

So, Side of 1st square = 60/4

⇒ Side of 1st square = 15 m

Now, we will calculate area of 1st square,

⇒ Area of 1st square = side²

⇒ Area of 1st square = 15²

⇒ Area of 1st square = 225 m²

And, Perimeter of 2nd square = 144 m

So, side of 2nd square = 144/4

⇒ Side of 2nd square = 36 m

Now, we will calculate area of 2nd square,

⇒ Area of 2nd square = side²

⇒ Area of 2nd square = 36²

⇒ Area of 2nd square = 1296 m²

Now, it is given that,

∴ Area of 3rd square is equal to sum of area of two squares

⇒ Area of 3rd square = 225 + 1296

⇒ Area of 3rd square = 1521 m²

Now, side of 3rd square = √Area

⇒ Side of 3rd square = √1521

⇒ Side of 3rd square = 39 m

Now, we will calculate perimeter of 3rd square,

⇒ Perimeter of 3rd square = 39 × 4

⇒ Perimeter of 3rd square = 156 m

Hence, Perimeter of 3rd square = 156 m

Answer 2

Answer:

All the sides of a square are of equal length

Side of a 1st Square = 60/4= 15 m Side of a 2nd Square = 144/4= 36 m

Area of a required Square

= (Area of a 1st Square) +(Area of a 2nd Square)

= 15²+36²

= 1521

Side of a required square = 39 m Perimeter of a required square = 39 × 4

= 156 m

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Comment :

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