Question

the perimeter of two squares are 60 cm and 32 cm respectively. Find the length of the diagonals of the sqare whose area is equal to the sum of the areas of these two sqares

Answer 1

Answer:

Diagonal of large square= 17√2 cm or 24.041 cm

Step-by-step explanation:

Perimeter of square is given by

= 4× side

The side of first square :

$a1 = \frac{60}{4} = 15 \: cm$

Side of second square:

$a2 = \frac{32}{4} = 8 \: cm$

Area of square1+ area of square 2:

${a1}^{2} + {a2}^{2} \\ \\ = {(15)}^{2} + {(8)}^{2} \\ \\ = 225 + 64 \\ \\ area \: of \: large \: square= 289 \: {cm}^{2}$

Side of large square

$= \sqrt{289} \\ \\ = 17 \: cm$

Diagonal of large square

$= a \sqrt{2} \\ \\ = 17 \times \sqrt{2} \\ \\ = 17 \times 1.414 \\ \\ = 24.041 \: cm$

Hope it helps you.

Answer 2

Answer:

Diagonal of large square= 17√2 cm or 24.041 cm

Step-by-step explanation: