Question

the perimeter trianglur field is 135 m and its sidrs are in ratoo 25:17:12 find its area using heron's Formula​

Answer 1

Step-by-step explanation:

Perimeter=135cm

Let the ratio be. 25x,17x,12x

25x+17x+12x=135

54x=135

x=135/54

x=2.5

Putting the value 12x=12×2.5=30

17x=17×2.5=42.5

25x=25×2.5=62.5

Sides of triangle are 30 cm,42.5cm,62.5cm

Area of triangle=1/2bh

=1/2×62.5×42.5

=2656.25/2

=1328.125

Answer 2

Step-by-step explanation:

Given-

Perimeter of Δ=135m

let the sides be 12x ,17x and 25x

25x+12x+17x=135

54x=135

x=135/54

x=2.5

so the sides are

a=12x2.5=30

b=17x2.5=42.5

c=25x2.5=62.5

So,

semiperimeter(s)= perimeter/2

=135/2

=67.5

By Heron's formula-

Area of Δ=√s(s-a)(s-b)(s-c)

=√67.5(67.5-30)(67.5-42.5)(67.5-62.5)

=√67.5(37.5)(25)(5)

=√67.5x4687.5

=√316406.25

=562.50 sq.m

HOPE THIS HELPS YOU .