Question

the perimetere of a triangle is 11y square -9y +13 and its two sides are 4y square -3y -7 and 5y square -4y+6 find the thir side of triangle ​

Answer 1

Answer:

2y^2 - 2y + 14

Step-by-step explanation:

Given that,

2 sides of triangle are : 4y^2 - 3y - 7 and 5y^2 - 4y + 6

So,

(4y^2 - 3y -7) + (5y^2 - 3y + 6) = 9y^2 - 7y - 1

3rd side of triangle = perimeter - sum of 2 sides

= 11y^2 - 9y + 13 - ( 9y^2 - 7y - 1

= 2y^2 - 2y + 14

Hope it helps