the perimeterof a rectangle is 104 m and its area is 640m .find its leangth and breadth.
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let the length be l and the breadth be b
perimeter=104m
which implies 2*(l+b)=104
which implies l+b=52
so l=52-b
area=640m^2
l*b=640
(52-b)*b=640
b^2-52b+640=0
now solve it by factorization
perimeter=104m
which implies 2*(l+b)=104
which implies l+b=52
so l=52-b
area=640m^2
l*b=640
(52-b)*b=640
b^2-52b+640=0
now solve it by factorization
hrishikase5h:
i get ans..
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