The perimeters of 2 squares are 192cm and 56cm. Find the perimeter of a square whose area is equal to the sum of the areas of 2 squares?
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Length of a side of square having perimeter 192 = 192/4 = 48 cm
Similarly, length of side of square with perimeter 56 = 56/4 = 14 cm
Since area of a square = (side)^2,
Total area of both squares = 48^2 + 14^2
= 2500cm^2
Let side of square whose perimeter is to be found be x cm
Then, according to given question
x^2 = 2500
X = 50 cm
Therefore, it's perimeter is equal to 50*4 = 200cm
Cheers, hope this helps dear!!
Similarly, length of side of square with perimeter 56 = 56/4 = 14 cm
Since area of a square = (side)^2,
Total area of both squares = 48^2 + 14^2
= 2500cm^2
Let side of square whose perimeter is to be found be x cm
Then, according to given question
x^2 = 2500
X = 50 cm
Therefore, it's perimeter is equal to 50*4 = 200cm
Cheers, hope this helps dear!!
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ANSWER:-
200cm or 2m
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