Question

The perimeters of ∆ABC and ∆DEF are 12cm and 48cm respectively such that ∆ABC⁓∆DFE and BC = 5cm then find FE.

Pls Answer Fast!!
​

Answer 1

Given in △ABC, D,E,F are the mid points of sides AB,BC and CA respectively

Now using mid point theorem line segment joining the mid points of two sides is parallel to third side and also half of it.

∴DF=21BC

⇒BCDF=21 __i

Similarly ACDE=21____ii

ABEF=21_____iii

Using (i),(ii) and (iii)

BCDF=ACDEABEF=